m^2=9/121

Solution for m^2=9/121 equation:

m^2=9/121

We move all terms to the left:

m^2-(9/121)=0

We add all the numbers together, and all the variables

m^2-(+9/121)=0

We get rid of parentheses

m^2-9/121=0

We multiply all the terms by the denominator


m^2*121-9=0

Wy multiply elements

121m^2-9=0

a = 121; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·121·(-9)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-66}{2*121}=\frac{-66}{242}
=-3/11
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+66}{2*121}=\frac{66}{242}
=3/11
$